Masses of common quarks are revealed
May 3, 2010 By Anne Ju
Quarks exist in a soup of other quarks, antiquarks and gluons within a proton or neutron. Determining their mass has been difficult due to the strong force that binds them together. (Christine Davies/University of Glasgow)
(PhysOrg.com) -- A research group co-founded by Cornell physics professor G. Peter Lepage has calculated the mass of the three lightest and, therefore, most elusive quarks: up, down and strange.
Quarks, the elementary particles that make up protons and neutrons, have been notoriously difficult to nail down -- much less weigh -- until now. A research group co-founded by Cornell physics professor G. Peter Lepage has calculated, with a razor-thin margin of error, the mass of the three lightest and, therefore, most elusive quarks: up, down and strange.
The work of Lepage, the Harold Tanner Dean of the College of Arts and Sciences, and collaborators from several international institutions, is published online (March 31) and in print in Physical Review Letters (Vol. 104:13).
The findings reduce the uncertainty of the quark masses by 10 to 20 times down to a few percent. Scientists have known the mass of a proton for almost a century, but getting the mass of the individual quarks inside has been an ongoing challenge. The quarks are held together by the so-called strong force -- so powerful that it's impossible to separate and study them. They exist in a soup of other quarks, antiquarks and gluons, which are another type of particle.
To determine the quark masses, Lepage explained, it was necessary to fully understand the strong force. They tackled the problem with large supercomputers that allowed them to simulate the behavior of quarks and gluons inside such particles as protons.
Quarks have an astonishingly wide range of masses. The lightest is the up quark, which is 470 times lighter than a proton. The heaviest, the t quark, is 180 times heavier than a proton -- or almost as heavy as an entire atom of lead.
"So why these huge ratios between masses? This is one of the big mysteries in theoretical physics right now," Lepage said. "Indeed it is unclear why quarks have mass at all." He added that the new Large Hadron Collider in Geneva was built to address this question.
According to their results, the up quark weighs approximately 2 mega electron volts (MeV), which is a unit of energy, the down quark weighs approximately 4.8 MeV, and the strange quark weighs in at about 92 MeV.
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May 03, 2010
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May 03, 2010
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If there are particles not affected by gravity floating around, would we not be looking at a large discrepancy??? hmm...
May 03, 2010
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May 03, 2010
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May 03, 2010
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http://www.iop.or...23/1/004
May 03, 2010
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May 03, 2010
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May 03, 2010
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May 03, 2010
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I love it when high school drop-outs with no background in physics try to explain what the real scientists should have said.
May 03, 2010
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May 03, 2010
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Why couldn't EMR have a rest mass but no mass when traveling at the speed of light?
May 03, 2010
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http://adsabs.har...96h3602L
May 03, 2010
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Therefore the rest mass of photon is rather complex question in advanced theories.
May 03, 2010
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May 03, 2010
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Please also note that there is a difference between rest mass and effective mass. Rest mass is the mass (energy) that an object takes on when it is not moving. Effective mass is E/c^2=[m^2+(p/c)^2]^(1/2). Photons, as far as we can tell have energy E=pc, and if you have a non-moving photon, you don't actually have a photon.
May 03, 2010
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For example if you have two one kilo mirrors separated by one meter, and a bunch of photons bouncing between them with an energy equivalent to one kilo of matter, how much does the whole thing weigh when put on a scale?
2 kilos or 3 kilos?
Alternatively if you have a super laser emit 1 kilogram worth of photons, your laser just decreased in mass by one kilo, resulting in a change in the curvature of spacetime.
Did the laser just emit a buttload of gravitons along with the photons? Or did the photons emit gravitons as they were escaping the laser? Did a strong gravity wave just leave the laser along with the light? Or is the "gravity wave" trapped inside the photons?
Maybe one of you guys can give me an adequate explanation.
May 04, 2010
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May 04, 2010
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Mass can be looked upon as "energy density". And therefor - anything that has energy potential, has a "mass potential" aswell.
A photon is an energy carrier (eg. has energy potential), so in this regard, it has to have "mass", sort of..
A gluon is a "virtual particle", virtualized (postulated) to fill a gap. So wether it has mass or not, is - at least for now - just subject of mere speculation.
This should answer a couple of the questions posted above aswell :)
May 04, 2010
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May 04, 2010
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May 04, 2010
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May 04, 2010
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Even though photons do not directly exhibit rest mass, they still have what I would call a "rest-mass potential". As soon as they get captured (by space-curvature, eg. black hole), this potential will automaticaly and directly contribute to the rest mass of the captor.
And apart from that, I don't really like definitions based on the "planck stuff", as they tend to (quite literally) "break apart" at small enough scales :-P
May 04, 2010
Rank: 2.3 / 5 (3)
Guess we both would be quite surprised, how far that "very definition" is, from what the very definition will be in a couple of decades/centuries :)
But even this definition has allready some very truth to it - it means, that if you have an infinitesimally small "charged particle", then you would have infinitesimally small photons/quanta as well :)
May 04, 2010
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Of course special relativity cannot predict it's postulates : http://en.wikiped...ativity, that the speed of light is absolute.
Also, since there is no rest frame of the photon, you cannot define a rest mass in the same sense.
The photon is not just a concept of quantum mechanics. The photon concept is a result of the combination of the classical equations of electrodynamics with quantization. Also, with just classical electrodynamics, you CAN show that the statistics of light trapped in a box is the same as that of trapped particles of some average energy.
A harmonic wave is equivalent to a delocalized photon.
they both obey maxwell's equations and hence have the same speed
May 04, 2010
Rank: 4 / 5 (4)
The standard model demands that carriers of forces with infinite range have a zero rest mass. This includes photons( carriers of the the electromagnetic force), and gravitons. While its possible that the standard model is incorrect, it has been experimentally verified to so many decimal places, its pretty unlikely in such a fundamental assumption.
May 04, 2010
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http://en.wikiped...meopathy
May 04, 2010
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May 04, 2010
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May 04, 2010
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When an atomic electron absorbs a "photon-wave", this wave collapses and its speed becomes zero relative to the inerial refrence frame of the atom. The "photon-wave" thus entangles and add mass to the original electron wave, which then has to morph into a higher energy wave. This morphing has erroneously been called a quantum jump.
This mechanism also happens when a light pulse is stopped within Bose-Einstein Condensate; and can only happen when the matter wave is a single holistic wave that is in instantaneous contact with itself over its whole intensity distribution in three-dimensional space.
May 04, 2010
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May 04, 2010
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May 04, 2010
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On topic: No, the standard model of particle physics does not deal exclusively with higher energies.
P.S.: Well, he just deleted his comment. :)
May 04, 2010
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May 04, 2010
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Delocalized photon is an oxymoron, as such photon would fill whole observable universe. And vice-versa: when wave is confined into limited space, it cannot be harmonic anymore. You're just confusing well understood concepts.
May 04, 2010
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May 04, 2010
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May 04, 2010
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http://www.scienc...1725.htm
May 04, 2010
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ZeroX:
A harmonic wave's momentum has no uncertainty so that p=k. This is true of all "photons" no matter what their length seems to be to an observer. It is possible because a "photon" has no inertia. Therefore it is in effect infintely long even though it can collapse to seem smaller within the inertial refrence frame of the observer.
Neodim: Not even a confined quark exists. Just like the Higg's boson does not exist. All these "particles" are derived by using nonsense like order parameters and spontaneous symmetry breaking!
May 04, 2010
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Correction: I meant a COHERENT harmonic wave
May 04, 2010
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May 04, 2010
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That works for the higher order elements in the periodic table as well. The most massive elements have the shortest shelf-life.
May 04, 2010
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Please stop confusing mass with REST MASS. When talking about the mass of a "particle" it is its rest mass. Any mass above that is a relativistic effect relative to an observer who is not moving with the "particle". It is a kind of REAL illusion; just like the slowing of a clock which does not REALLY happen within the refrence frame within which the clock is actually stationary.
May 04, 2010
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No, it's one guy/girl with access to a lot of physics papers and a large clipboard by which to copy and paste excerpts that it thinks agree with it's philosophical view of the universe.
Wanna see a trick, ask it to do math.
May 04, 2010
Rank: 3.3 / 5 (7)
After all, most of people are generally more interested about explanation of reality - just after then about regressions of it (this is the job for small group of specialists). To avoid blind regressions, we are forced to understand the Universe first.
Without it our approach would be similar to attempts to solve homework by random guessing of various combinations of equations - which is the stance, which is usually punished in schools. A good teacher learns the kids to understand problem first.
Scientists who are payed for time rather for real advance in understanding aren't very motivated in such approach in general, because it enables them to maintain their jobs & secrets longer. They're like priests of modern era.
May 04, 2010
Rank: 3.3 / 5 (7)
Frankly, what these mainstream physicists could really get from introduction of some Theory Of Everything? Most of them would only risk their jobs. This is why they're adhering to their math models so much - it keeps them separated them from the feedback of publicity in similar way, like the usage of Latin words between doctors and lawyers.
May 05, 2010
Rank: 2.3 / 5 (3)
Amen. The theoretical physics church-sect has since 1927 become worse than any fundamentalist religion can EVER hope to be. The time has come to clean the rot!
May 05, 2010
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May 05, 2010
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I have done so for 10 years and reconciled my theories to the point of being self-consistent (see my website) but the "practioners" block everything that is not mainstream. They have not learned what Einstein meant when he reponded to the book "100 authorities against Einstein" by saying "why 100 authorities when a single small fact should have been sufficient!"
Try and get these knuckleheads to discuss the single small fact that according to Born's interpretation of the intensity of a wave function the most "probable position" to find an electron is usually where the wave function has zero intensity! No ways will they even consider the implications of such a single small fact!
So stop spouting claptrap XeroX
May 05, 2010
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Though I would like to see your website, if you want to post it or PM a link.
May 05, 2010
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May 05, 2010
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It is simple to do it by yourself. The simplest calculation is to derive standing Schroedinger waves in a box. The lowest energy one (n=1) has a maximum which corresponds to the most probable position (mpp) of the electron. But when calculating the mpp for n=2 you will find it is at a node where the intensity distribution is zero. This is so for all the solutions for which n is even. Another interesting calculation is to calculate the mpp for n=3. It corresponds to a maximum: BUT there are now THREE maxima with the same intensity: So why should only one of them be the mpp? It is of course a mockery to derive Heisenberg's "uncertainty" for position around a mpp of zero or one for which there are equal probabilities at other positions. Why this simple fact has not been picked up over the past 80 years astonishes me.
What mortifies me is that I have accepted it for many years myself!
May 05, 2010
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Unfortunately this is the inheritance the Copenhagenists left us, with which I disagree fully. Why would you follow this route if you can interpret your description of the universe to be comaptible with cause and effect and classical mechanics?
A clue: Note that my e-mail is at cathodixx (note the double x, which means two surfaces)
May 05, 2010
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http://tinyurl.com/2wr64fq
May 05, 2010
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The article states that the quarks measured were those comprising protons. At the same time, it states (third paragraph from the end) that "Quarks have an astonishingly wide range of masses. The lightest is the up quark, which is 470 times lighter than a proton. The heaviest, the t quark, is 180 times heavier than a proton -- or almost as heavy as an entire atom of lead."
My question is therefore how a quark can have a greater mass than a proton, much less an entire atom of a heavy element.
May 05, 2010
Rank: 3.4 / 5 (5)
Dense aether theory considers vacuum as a sort of dense supercritical fluid, so it can explain such question at least conceptually: inside of such fluid a nested density fluctuations can be observed and the strange and top quarks correspond the various levels of nesting.
http://tinyurl.com/33cvqv6
You can imagine, the density of vacuum is so high, that even vortices of such fluid are behaving like solid particles (a tiny 3D gyroscopes, or something similar) - so these vortex particles can form another generation of fluid with density fluctuations in it and so on, thus forming the three known generations of particles.
These heavy nested vortices are the less stable, the higher the nesting level is, though. We can imagine formation of more stable heavier particles at the core of massive neutron stars, for example.
May 05, 2010
Rank: 3.4 / 5 (5)
But when the intensity/frequency of jumping increases, a parasitic vortices are formed, so called Widnall's instability:
http://tinyurl.com/32q5nwl
This is because the inertia of environment, which is rotating in torsion deform, cannot be neglected anymore. If the frequency/energy density of fluctuations increases even more, the another generation of deformations could be formed, which accumulates even higher energy.
So I presume, the particle generations of quarks could be modeled by nested vortex fluctuations of sufficiently dense elastic fluid, supercritical vapor in particular.
May 05, 2010
Rank: 1 / 5 (2)
Yes I respect the concept of a time-independent matter-wave but not three or more "uncertainties" per wave. It violates Heisenberg's original postulate. Neither do I respect an "uncertainty" in position around a position at which the wave has ZERO intensity. All harmonic waves have their intensities equal to their energies. So why should a matter-wave be different? The energy of a matter-wave is its mass and its "most probable position" is OBVIOUSLY ITS CENTRE OF MASS.
Please can you for once use your own brain and not post irrelevant references to websites! Or is this just too much for you?
May 05, 2010
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Congratulations! This is a brilliant question and further proof that we need people like you with common sense to prod the physics community. Except that "quarks" are nonsense the fact is that all so-called "fundamental particles" are excited states of fundamental waves: They are light waves, electron-waves. proton-waves and neutrino-waves. Excited states are NOt fundamental "building" blocks of matter and never will be!
May 05, 2010
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Anybody who can understand this gobblydook needs help.
May 05, 2010
Rank: 3.4 / 5 (5)
Some people consider, the Universe is formed by interior of dense star or black hole - so we can just speculate, how such extremely dense particle stuff should appear and behave. Even subtle density fluctuations of such extremely dense fluid or gas would behave like distinct particles.
Surprisingly, a very little is known about behavior, geometry and appearance of extremely dense phases of matter.I didn't talk about "excited states", in the connection with fundamental blocks of matter the less. You're fighting with ghosts...
May 05, 2010
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May 05, 2010
Rank: 3.4 / 5 (5)
These elementary vortices aren't formed by close loops, so they're unstable - but they could stabilize itself by their mutual merging into close loops in various ratio. We can imagine them as a sort of spiral LEGO kit.
http://tinyurl.com/34d9qpx
The animation above illustrates the schematic formation of proton and neutrons from up and down quarks. We can see, how fractional charge (1/3 and 2/3) is represented in this knot model by various degrees of loop convolution. In addition, we can see the fixed mixing ratios of individual quarks, which are described by fixed mixing angles of Cabbibo matrix in Standard model.
May 05, 2010
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Judging by the resposes to this article, I would say that this is important research that needs to be done to resolve all the conflicts above. forgive my simplicity, but I am new.
May 05, 2010
Rank: 3.4 / 5 (5)
From this perspective, the aether model is just an attempt to explain most relevant mainstream theories in simple, consistent and intuitively understandable way, which is enabled for more exact particle simulations later.
Why? Simply because we collected many indicia, such explanation is possible.
My feeling is, the attitude of yours is exactly as opposite. You're not trying to explain existing theories, but to deny them. I'm not saying, mainstream physicists are very happy, when some layman proposes his own interpretation of their theories - but it's still better, then to deny them completely.
May 05, 2010
Rank: 3.4 / 5 (5)
The concept of inhomogeneous environment similar to condensing supercritical fluid explains it well. Due the partial condensation of gas into fluid such system appears like dynamic foam or sponge, which could serve as a model of quantum foam, forming the vacuum.
In such system the energy spread in both transverse waves along surfaces of density fluctuations like light, both in longitudinal waves like gravitational waves. Light waves are relatively slow, but they transfer high energy density. Gravitational waves are much faster in this model, but they spread only subtle energy density.
The trick here is, vacuum appears so huge, because of large ratio between speed of both kinds of waves due the immense density of environment.
May 05, 2010
Rank: 3 / 5 (2)
A matter-wave has an intensity which is equal to its mass; since mass is energy: Therefore it has a centre-of mass. A body with a centre of mass moves as if it is a particle: Thus a wave with mass-energy can also move as if it is a "particle" which it is NOT. When such a wave encounters boundary conditions which forces it change its shape and size, wave properties, as we know it, appear. The fact is that it has all along been a wave. There is NO "wave-particle duality" or complementarity since "particles" just do not exist.
It is really so simple: CAN NOBODY UNDERSTAND THAT JUPITER MOVES AS IF IT IS A POINT PARTICLE WITH ALL ITS MASS AT ITS CENTRE OF MASS? EVEN ARCHIMEDES KNEW THAT THIS WOULD BE THE CASE! WHAT HAS BEEN WRONG WITH BOHR?
May 05, 2010
Rank: 3.7 / 5 (3)
You do not really think one should waste time trying to engage you in logical discourse, do you?
May 05, 2010
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We can model the behavior of vacuum for example by careful cooling of supercritical fluid into point of condensation, where such system appears like intimate mixture of foamy droplets of gas and fluid and to measure the speed and energy density of sound waves, which are passed through such mixture (so called quantum critical point, i.e. Lifshitz point).
In this moment the maximal energy density is reached, so we can say, we got the physical model of vacuum, in which energy could spread as intensively, as possible. Note the connection of this model to another modern theory of quantum gravity - the Horava-Lifshitz theory, which models vacuum as an anistropic mixture of space and time in its quantum critical point.
http://tinyurl.com/35tx6ne
May 05, 2010
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As the result, every energy wave spreads through such environment like less or more dense blob of foam, i.e. like wave packet, which has a center of mass due its positive surface curvature / gravity field around it. This explains, why light wave spreads through vacuum like stream of blobs, i.e. like shower of photons, too. The particle character is the more pronounced, the higher frequency the energy wave has - as the result, photons of gamma ray are forming sparks in scintillators like true particles.
May 05, 2010
Rank: 3.4 / 5 (5)
And the concept of center of mass is not so trivial too - for example, if photon is localized particle in spinthariscope or spark chamber, it would mean, it has finite surface curvature, center of mass and it behaves like real massive particle, transferring matter - not only momentum or energy. This is conceptual shift.
If photon would transfer only momentum and not mass, the hot glowing object or excited atom nuclei wouldn't lost it mass during cooling and/or de-excitation in accordance to E=mc^2 equation.
May 05, 2010
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May 05, 2010
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We should realize, during gamma ray burst of active galactic nuclei the energy corresponding mass of whole sun is released in single moment. Such giant burst of energy has its own gravity field too, so it tends to propagate like single body or even trap some random photons into it from outside.
Well - and if we can explain the gravity of energetic photons, we can explain the mass of heavier bosons, too.
May 05, 2010
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After all, everyone can see, you are appearing rather like particle, then the wave. And the particle-wave duality is simply experimentally proven stuff. In notion of dense aether model every particle appears like less or more dense blob of quantum foam, which could be considered as a tiny fuzzball of strings. The stable cluster of photons rolling across whole universe could be considered as a good prototype (mirror matter) of particle at Planck scale.
May 05, 2010
Rank: 5 / 5 (2)
In this regard, it's much propper to imagine the photonic "wave-front" as the surface of an expanding baloon, where the wall thickness coresponds to radiation intensity. No matter how big the balloon is, there will allways be a trace of the radiation, just with dropping intensity as the distance from centre increases. So perfectly non-dispersive propagation of G-rays is simply not real
May 05, 2010
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May 05, 2010
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The problem of many abstract theories is just the fact, they don't reflect observable reality at sufficiently global scale. We simply cannot observe a pure radiation in the same way, like we cannot have a well defined pin-point particle.
May 05, 2010
Rank: 3 / 5 (2)
http://arxiv.org/.../0703260
If we can see some objects more regular, it's the consequence of the fact, we are objects limited in size and energy density, so that most of extremities remains hidden before our eyes and most of fractal objects are quantized and equalized into limited number of categories.
We should always distinguish the description of infinitely random reality from abstract exsintric perspective and from perspective, which is really observable by some limited creatures and their just a bit less limited devices.
May 06, 2010
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All I can say after reading your ideas which are all based on unproven speculation is to quote Mark Twain: "Today I have met a man who knows more things that are not so than any other man I have ever met".
Light in vacuum does not have rest mass while an electron-wave has. Therefore a "free electron" MUST be able to be stationary within its own inertial refrence frame. This in turn demands that it MUST have a centre of mass which is stationary within this same inertial refrence frame; or else all the laws of physics have to be re-invented: Also the Schroedinger equation. Since the centre-of-mass MUST be stationary there cannot be any uncertainty relationship between position and momentum. Heisenberg's uncertainty relationship for position and momentum is just the normal relationship for ANY harmonic wave since such a wave exists within both position and k-space. Therefore Planck's constant appears on both sides of Heisenberg's relationship: And therefore it cancels out.
May 06, 2010
Rank: 1 / 5 (2)
This still doesn't say, this inertial reference frame must remain stationary too. Because vacuum is particle gas, every particle in it is attacked by collisions of surrounding particles like pollen grain in water excerting Brownian motion. We can observe it at the case of lightweight atoms, like those of liquid hellium - such liquid never freeze at room pressure, even at absolute zero. It can serve as a tangible evidence, reference frame of particles isn't complete stationary.
May 06, 2010
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This remark is incontrovertible proof that you do not understand the most important foundation stones which had been laid by Galileo, Newton and Einstein, and on which ALL physics MUST be based.
An inertial reference frame is defined as a reference frame within which one CANNOT perform ANY physics-experiment to determine whether the reference frame is moving or not. If your physics requires that it must be moving, as you have just indicated that it must, it is wrong: Unless you have new laws that can replace those of Galileo, Newton and Einstein.
May 06, 2010
Rank: 3 / 5 (2)
It's just the accidental story of yours (extrapolation of your figth against BCS theory, I presume), you're fighting against QM by using of SR postulates. I could refute special relativity by strict adherence to quantum mechanics postulates instead without problem.
I indeed know, special relativity is deterministic theory, so it violates indeterminism of special relativity and vice-versa - but such insight is just a trivial finding. Sorry, but you simply CANNOT extrapolate SR theorems to QM phenomena and vice-versa. These two theories aren't consistent and one violates the another one.
May 06, 2010
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The only reason why you find them not consistent is because the Copenhagen interpretation of QM violates all the equations ever derived in physics. Even Schroedingere's equation accepts that an electron has a rest mass: Rest mass means that such an entity must have an inertial reference frame within which it is stationary. And such a body CANNOT have uncertainties in the position and momentum of its centre-of-mass. Schroedinger's equation and SR are totally consistent as soon as one drops the "probability-interpretation" for QM. In fact the wave-equation for mater-waves is then also consistent with Einstein's gravity.
The "troll" who upvoted me obviously understands far more than you are capable of understanding!
May 06, 2010
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May 06, 2010
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Nope, because he upovotes crackpot ideas without any experimental evidence.
Copenhagen interpretation of QM doesn't care about center of mass at all - it's probabilistic interpretation of QM and as such it fits all the observations, which fall into realm of QM. It was confirmed by experimental tests of Bell's inequality. And it fits dense aether model of vacuum well.
May 06, 2010
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I doubt it, because from Schroedinger's equation of free particle wave follows, this particle wave would expand into infinity - whereas from Einstein's relativity follows, it should collapse into singularity like geon.
In fact, QM doesn't recognize "Einstein's gravity" at all and the existence of gravity cannot be derived from it - until you demonstrate the opposite (and deserve Nobel price in such way).
May 06, 2010
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Typical is it not!
May 06, 2010
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Exactly! This is why it is based on virtual reality!
It most certainly does not. As I have already pointed out on this forum, this interpretation leads to the conclusion that the "most probable position" for an electron is at a position where the probability to find an electron is excatly ZERO!
It was NOT confirmed by tests of Bell's inequality at all. How? Of course it fits your aether model since this model is also virtual reality.
May 06, 2010
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Of course it does. If you interpret a wave-intensity as a "probability" instead of a mass-energy you will obviously have a contradiction!
Only because of the stupidity of the probability interpretation. When you accept that the intensity of a harmonic matter wave is its energy, as is the case for ALL harmonic waves ever discovered; you will realise that this intensity represents the mass of the wave-entity AND the curvature of space around the mass. (the latter curvature is wrongly interpreted in terms of probability as "tunnelling tails)
Are you going to nominate me? Thanks!
May 06, 2010
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This is quite common situation in other theories, too. For example the center of mass of Jupiter-Sun (or whole solar system) lies outside of surface of Sun. Which basically means, with respect to Newtonian physics all planets are revolving just an empty place of space. Even with respect to relativity theory such result is "strange", because the center of gravitational lensing lies at the empty space. Statistically most of asteroids or comets would fall into empty point of space outside of Sun
May 06, 2010
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How to reconcile theories, which apparently predict quite opposite results? Aether theory proposes one of the ways: I believe, it could be possible to demonstrate by solution of wave equation in sufficient number of dimensions, the 4D slice of such solution representing our space-time fulfills both theories at least approximately. If you can derive it in formal way, you could visit Stockholm for Nobel price about quantum gravity.
May 06, 2010
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Probabilistic interpretation of QM is quite OK, simply because our Universe IS of probabilistic nature. Even simple water droplet demonstrates it - you cannot derive the behavior of water molecules inside of droplet just by careful observation of droplet's surface. The molecules inside are dancing in extradimensions with respect to droplet surface - so that the substantial part of information about their motion is unavoidably "lost" there (i.e. widespread over large area of CMB noise).
The probabilistic character of QM is a logical consequence of hypergeometry from this perspective.
May 06, 2010
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The probability interpretation was allways just a crude placeholder - sufficient for basic calculaions and statistics - but we are nearing a breaking point in physics, where it either will need to go and make room for something more "sophisticated", or we stay in caves for some longer.
Though we will never be able to predict the outcome of infinite-complexity systems with a 100% certainity, we at least need to push the probability approach into "deeper levels", somewhat..
May 06, 2010
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After all, it was just Albert Einstein again, who once said, "reality is merely an illusion, albeit a quite persistent one".
Why not, aether theory is about it. But it doesn't disprove this interpretation, but it explains it in wider context.
May 06, 2010
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So you agree with me that the "most probable position" of a matter wave is really its centre of mass! Thanks this is exactly what I am trying to say all along. It has NOTHING to do with probability!
Please stop punting a ridiculous theory under different names: Alizee, Seneca? Xerox? and what have you!!!
May 06, 2010
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As the result, we would see, all observations are blurred by omnipresent noise of Brownian motion of particles of underwater. We couldn't see such particles though, because just the water molecules are mediating surface waves and no object can serve both as a object, both the subject of the same observation.
But we could observe tiny density fluctuations of water surface, which are 2D analogy of cosmic microwave background. This analogy works perfectly.
May 06, 2010
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In the system Jupiter - Sun above mentioned, most of asteroids would fall into center of mass of this system, i.e. even from Newtonian mechanics the center of mass correspond the maximal probability of gravitational activity of that system. In notion of dense aether theory the whole quantum mechanics is just about probabilistic description of many body systems.
As we know, formal math cannot describe even the motion of three gravitating bodies reliably - but it can describe the probabilistic distribution of their center of mass.
May 06, 2010
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Please STOP deliberately to confuse "normal probability" used when modelling many bodies with QM probability involving a SINGLE entity. You are not REAALY as stupid as this, ARE YOU?
Nonsense: The fact that the double slit diffraction pattern disappears when a moren tries to measure through which slit the "particle" came proves that there was a wave which moved through both slits which is then modified when being measured behind the slits. This is the way ALL waves react: When you change the boundary conditions the wave morphs into a new cofiguration.
May 06, 2010
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I wish you would take a course in simple logic and stop throwing words around which have nothing to do with the experimental facts!
May 06, 2010
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I never proposed anything, which couldn't be modeled at least conceptually by using of few trivial tools: water surface, soap foam, supercritical fluid, mercury droplets... did I forget something? If something remains ridiculous here, then it's only the fact, nobody has attempted to use it before. For me the whole theoretical physics is just a sort of kindergarten - if you don't care about exact numbers, everything is clean, simple and transparent here.
May 06, 2010
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If you are not able to realise that this probability has NOTHING in common with QM probability, then the time has come for you to find a job as a street sweeper!
May 06, 2010
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Yes you have: It it is known as "common sense"!
May 06, 2010
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http://www.physor...511.html
I presume, in near future these experiments will become as iconic, as the M-M experiment, for example. They're giving a "common sense" to abstract theories.
May 06, 2010
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It is an obtuse demonstration that individual waves can form a macro-wave by entangling to, in the process, lose their individual existences. This is exactly what i have achieved with the electron-waves I have extracted from a diamond, which then form a superconducting holistic wave through which electron-charges are teleported. It has NOTHING to do with your concepts on so called aether theory. Sorry to disappoint you!
May 06, 2010
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So you can send some star into galaxy, for example - there will be only very subtle probability, your star would collide with some star inside of galaxy. After then you could replace the action of individual stars by their collective gravitational field, which has center of mass well outside of real massive bodies.
As we know, due the dark matter content, the whole galaxy behaves like giant piece of solid jelly. You could use the whole galaxy as a rigid optical lens for focusing of path of isolated stars in similar way, like optical lens for photons, for example.
May 06, 2010
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Such God could easily obtain a feeling, the only real particles in his toys are just these central black holes - the whole rest of their matter remains invisible for Him and it manifests only by force fields "at distance". Of course, all these fields are still full of invisible stars, which are mediating these forces at proximity.
Richard Feynman: "There's Plenty of Room at the Bottom"
http://en.wikiped...e_Bottom
May 06, 2010
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May 06, 2010
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I am not even going to waste my time to try and argue with you over "galaxies" and what have you. Nonetheless, "single particles" do not exist: ONLY waves where matter waves have rest masses and centres of mass and light waves in vacuum have no rest masses. Only when a light wave moves through a material does it acquire inertia and thus part of its energy becomes rest mass. That is why these waves are also modelled in terms of complex wave amplitudes; just like matter waves!
Bye until tomorrow!
May 06, 2010
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What will happen, if you achieve a sufficient electron density at the walls of pipe and put a single electron into it? Well, this electron will be repelled by most of surrounding electrons at the distance. It would refute to pass the pipe obstinately.... But when we push it by sufficiently strong force into pipe, we could observe, this electron travels through pipe freely, like electron through empty vacuum - while it still remains perfectly localized. We could use such pipe as a superconductive device, if we put some wires into both ends of it.
I presume, we could model similar device by careful arrangement of magnetized spheres, for example.
May 06, 2010
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I have no issues with "uncertainity" aswell, because as I have wrote before allready, you can not be 100% certain in a system with infinite-complexity. Any attempt to precisely pin-point a physical property of an entity by the means of mathematics is bound to fail - as there will allways be a margin of error.
I think that is exactly what Einstein was trying to express with the above quoted sentence, and it fits nicely with the basic Heisenberg interpretation.
Though problems arise when this kind of concept gets interpreted in a (certainly) wrong way, and one tries to build physical reality based on statistical "principles".
May 06, 2010
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http://en.wikiped...ic_force
F = T dS / dx =
= T . 2.pi.m = (spherical field should be produced by mass at the origin (Birkhoff theorem)
= 2E/N . 2.pi.m = ("T" expressed by using of the equipartition theorem (E = N kT/2).
= 2MG/A . 2.pi.m = ( "E" expressed as "M" by using (E=Mc^2) for the mass inside of sphere
= 2MG/(4.pi.R2) . 2.pi.m = ( area "A" expressed as "4.pi.R^2" for sphere surface.
= MmG/R2 (which is Newton's gravitational law
May 06, 2010
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Statistical Physics Offers Insight Into Moral Behavior
http://www.physor...642.html
From perspective of Aether theory the amoral people are like individualistic particles, whereas the moralists are like density fluctuations, following some laws or ethical principles. When the system is low of energy, then the need for mutual cooperation prevails and the people will start to behave cooperatively and morally.
So that the emergence of morality in human society is simply the phase transition of dispersed matter, like many others. For this purpose I'd considered morality as a tendency/ability of individuals to cooperate with the interests / follow established energy density gradients of society, which are serving like predefined paths for spreading of information/energy/material objects like gradient at water surface or space-time branes of string theory.
May 06, 2010
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With compare to formal models, numerical models are very stable, robust and sufficiently fast in most cases. Because particle concept is singular by its very nature, it can handle situations like vortex and singularity formations, where formal models tend to become poorly conditioned and unstable.
http://mike1336.web.fc2.com
The main point of particle models is, you're not required to derive and discretize differential equations, if whole observable reality is composed of particles anyway. So it can be modeled by particle simulations from scratch. If you don't know, how to model some phenomena, then the particle models are usually the most robust way, how to achieve at least some result
May 06, 2010
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Now we have a great parallel processors on the market, based on GPU vertex processing units used in common PC, for which such multibody particle simulations involving millions of particles are the piece of key.
http://www.youtub...=related
Why not to model the quarks by nested density fluctuations of nuclear fluid? I've no time for such stuff, but some experienced programmer could have.
May 07, 2010
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Stop overwhelming this forum with irrelevant nonsense. When talking about Copenhagen uncertainty, it is the so-called "inbuilt" uncertainty for a single electron according to which a measurement of its position, even if it could be done with 100% certainty, causes an infinite uncertainty in its momentum; and vice versa. It is the latter interpretation that violates the most fundamental law on which ALL physics has been formulated: namely Galileo's inertia; This concept has been quantified by Newton as rest mass. Thus any entity with rest mass cannot have such inbuilt uncertainty in position and momentum. It is this misinterpretation which makes it impossible to reconcile QM with Einstein's gravity. The statistical parameters and uncertainties, which you are obfuscating the argument with, are what one normally expects when one cannot measure with 100% accuracy and when working with many entities. The latter HAS NOTHING to do with Born's and Heisenberg's wrong interpretation
May 07, 2010
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Thank you.
May 07, 2010
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It's evident, quantum mechanics would violate the Galieo inertia in simmilar way, like the Galileo transform violates the relativity. Why only the relativity should violate Newtonian physics and quantum mechanics not? In aether model the Newtonian physics sits somewhere between relativity and quantum mechanics at distance and energy density scale. In water surface analogy the quantum mechanics manifests for wery short waves, which are affected by Brownian noise, whereas relativity manifests for very long waves, where compressibility of watter gets taken into account.
May 07, 2010
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http://www.almade...stm6.jpg
http://www.physic...img4.jpg
The later image illustrates the particle-wave duality too - the virtual "atom" at the center of quantum coral is formed just by interference of quantum waves from surrounding atoms. Such virtual atom is behaving like real one: for example it can exhibit a charge, which repels another particles, which are spreading around it.
May 08, 2010
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What is observed is proof that an electron is NEVER a particle but ALWAYS a wave with a centre-of mass. An extended body with a centre-of-mass can move like a particle even though it is not a particle. A wave with a centre-of-mass does NOT violate Galileo's inertia nor Newtons definition of rest mass. Thus it is fully consistent with ALL physics from Galileo to Schroedinger! It is not necessary to invoke inane concepts like "wave-particle duality" or "complementarity".
May 08, 2010
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Dense aether theory doesn't solve this symmetry too, it just makes it central to its philosophy. For human observer every object larger then the wavelength of CMB noise would appear like particle in wave environment, whereas all smaller objects would appear rather like waves in particle environment. Such conclusion follows from geometry of inhomogeneous unparticle environment.
Of course, you can build a formally relevant theory just by using of wave concept, for example by considering of wave equation in infinite number of dimensions in the same way, like to explain everything just by particle collisions - but it seems for me, we cannot explain everything just by waves or just by particles, so I gave my theory a mixed name to avoid easily predictable controversies.
May 08, 2010
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http://en.wikiped..._formula
This identity essentially maps every wave motion to circular vorticity in extradimensions of conjugated complex plane. For example for ripples at 2D water surface each particle does a circular motion in 3D space there, which could be assigned to the intrinsic vorticity (a spin density) of water surface (gradient). Vorticity is indeed a concept of particle environment (a fluid) - so you cannot have wave without particles in the same way, like you cannot have gradient without inhomogeneous environment.
Many attributes of electron (spin or charge) could be explained more easily by its vorticity, some other fits better the wave concept and I can live comfortably with it, because I can imagine, how these two concepts are related mutually in complex 4D geometry. So I wouldn't waste my time by convincing people about relevancy of only one concept from the above, being You.
May 08, 2010
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I've absolutely no problem with the definition of yours - I'm just saying, the wave concept is unbound, atemporal, spatially unlimited object without beginning or end. So for considering of something like "wave with center of mass" you're required to introduce a new condition of extradimensions on background, which is not contained in wave equation by itself and which makes such wave spatially localized like particle.
In dense aether theory the particle is every object, which is substantially smaller then the local space-time, in which such object resides.
May 08, 2010
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Therefore no object could become a pure wave or pure particle - with exception of the whole Universe, indeed. Without these nonlinearities we would have nothing to observe in it. Even Einstein was avare of it when he talked about the stress-energy of space:
"This space-time variability of the reciprocal relations of the standards of space and time, or, perhaps, the recognition of the fact that "empty space" in its physical relation is neither homogeneous nor isotropic, compelling us to describe its state by ten functions.., has, I think, disposed of the view that space is physically empty.
May 08, 2010
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Yeah, flat earth, with four corners, 6000 years old.
May 08, 2010
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I do not have the time to read through the rest of your meanderings: So I will only read what I have quoted and try to get you to reason logically for a change.
How and from what do you construct your "wave packet"? Schroedinger's equation for a free electron (V=0) does NOT give a wave packet but a time-independent wave with the same intensity which fills an infinite space. Such an electron is obviously nonsense.
May 08, 2010
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Wave packet (a soliton) is formed in spreading of wave through inhomogeneous environment, which becomes more dense under influence of energy wave like soap foam during shaking. There you can see simulation in Java..
http://tinyurl.com/y383ol3
May 08, 2010
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When normal wave introduces such environment, it spreads in less or more dense blob, which automatically balances the energy density of the wave inside. If it becomes more dense, then the wave spreading is slowed, frequency goes down and wave packet expands. When this blob becomes too sparse, the speed of wave increases, which increases the frequency of wave inside and energy density increases accordingly.
In this way, the resulting wave traveling inside of soliton maintains its energy density into fixed value like photon, transferring defined quantum of energy and the resulting blob of undulating foam remains stable.
May 08, 2010
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This insightful approach had a trivial problem, though - when gravitational wave collapses, then the space-time curvature increases in it, which results in larger gravity field, which increases the collapse even more. This result could be avoided though, if we consider, the curvature of space-time has not only energy density assigned by Einstein's equations, but it's own mass density by E=mc^2 equivalence - again!
This additional mass density surrounds every collapsing object like dark matter field, thus balancing gravity of the matter, which has created it, thus prohibiting the collapse of this matter into singularity.
May 08, 2010
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E = F . v = (m . v) . v
In this way the classical mechanics could save both quantum mechanics, both relativity before singular solutions.
May 08, 2010
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May 08, 2010
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Sometimes the second perspective is more abstract or even nonsensical (geocentric model over heliocentric one, for example) - but particle-wave duality appears quite symmetric and well motivated for me.
May 09, 2010
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Alizee, you see why one cannot have an intelligent conversation with you. You start of with general statements that you cannot prove; and then proceed to confuse the issues. "Quntum mechanics " cannot explain is a nonsense statement. It can mean that it will never be explainable or that the present crop of theoretical physicists are just incapable of getting their act together. I believe it is the last and that you are part of this confusion.
Correct! Because they do not understand what is really going on. Therefore they paddle along with impossible concepts like "dense ether theory"!
May 09, 2010
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So electrons consist of "soap foam". Please become real and talk sense. I have NEVER seen soap foam used to model bound electrons. The Schroedinger equation is the best approximation we have at present. So I am asking you how this equation can model a "wave packet" in free space and then you avoid it by blowing soap bubbles.
The fact is that the shape and size of ANY wave are determined by its boundary conditions. What are the boundary conditions in space which causes a wave packet? Wave packets only form from many electron waves superposing within conductors when one applies an electric field. The latter causes the boundary conditions which form them. How is this done for a solitary electron-wave obtained from Schr. Eq. (a single wave) in space?
May 09, 2010
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http://tinyurl.com/y24twwr
The same system is called a "string net liquid" or "spin network" or "protosimplex" in other theories.
http://dao.mit.ed...wen.html
The behavior of such mixture of dense aether and less dense aether is similar to soap foam, because becomes more dense reversibly, like soap foam shaken inside of evacuated vessel. Soap foam is only illustrative model of particular aspect of aether behavior - no less, no more. This aspect of behavior is called a CDT in LQG theory.
http://en.wikiped...gulation
May 09, 2010
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When some wave is formed at 2D wave surface, it can be described by common wave equation. But this wave does surface undulated in context of 3D space and as such larger. As the result, every wave slows down its own propagation, because it virtually "expands" its space-time around it. This effect is the more pronounced, the more water surface becomes curved, i.e. the higher the wave frequency is.
In 2D such behavior cannot be described any boundary condition - it could be described only by solving of wave equation in 3D instead of 2D space, because it's a product of extradimensions.
May 09, 2010
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It's completely formal, abstract process, which doesn't care about underlying physics at all, thus remaining separated from reality. We should realize, forty years old string theory has no experimental confirmation of it, yet. It's just validated with experiments occasionally and when confirmation is found, then the theory is claimed to be true.
Dense aether theory is based on idea, Universe is basically random stuff without any intrinsic structure. All structures are formed by exaggerating of statistical fluctuations in it because each gas is behaving so.
May 09, 2010
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The motivation of this approach can be understood in the light of some recent ideas, Universe is formed by interior of some black hole. Black hole is formed by collapse of very hot & dense matter, so we can imagine the vacuum as such matter easily.
http://www.physor...839.html
But dense aether theory doesn't require the concept of black hole at all, thus removing this unnecessary postulate from further thoughts. Instead of it, it explains, why every piece of Universe would appear, like if it would be formed by interior of black hole due the omnipresent dispersion of light in the vacuum, which blurs the remote areas into omnipresent noise of CMB fluctuations like foggy landscape.
May 09, 2010
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May 09, 2010
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The reason why this supposedly happens is because these equations are solved without stipulating boundary conditions. Any such solution is NOT physics. Furthermore by then superposing the possible "boundaryless" solutions as if they are all electrons is obviously nonsensiscal. Both Schr. and Dirac's equations are SINGLE ELECTRON equations so that just ONE of the possible solutions can be the electron! That means that a Dirac electron MUST have an energy of minus infinity!
When stipulating the correct boundary conditions there is no "spreading" whatsoever; just as it must be!
All derivations obtained by ignoring boundary conditions are voodoo. This is why ALL quantum field models are just plain nonsense.
May 09, 2010
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http://en.wikiped...ondition
Which is basically the main problem of this solution due the omnipresent CMB noise this potential can never remain zero on boundary - it exerts "pressure" to the free particle "from outside", thus keeping it at limited size. But quantum mechanics cannot derive the presence of CMB noise in the same way, like general relativity.
May 09, 2010
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But they weren't clever enough - they didn't realize, extradimensions are all around us - and the CMB noise is manifestation of hyperdimensional nature of space-time, too. Due the presence of CMB our space-time is not plain 3.0 dimensional - but let say 3.00000001 dimensional.
May 09, 2010
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Why you have to bring in concepts that cannot be tested experimentally to create a virtual reality you WANT to believe in, is beyond my comprehension.
It is just a simple fact that if you have to integrate once you have one constant which mathematics cannot supply, but has to be supplied by common sense. If you have to integrate twice, you have two constants etc. Stipulating these boundary conditions IS physics, avoiding them is "beautiful mathematics' which Dirac propagated, but has NOTHING to do with physics whatsoever. If you derive a solution which requires an infinite space within our universe, which is NOT infinite, as you guys have been doing consistently for 80 years now, you are not doing physics. I do not know what to call it other than pure nonsense!
Schroedinger's wave equation requires THREE integration constants: One for time and TWO for space. So please, do some physics, and give me the two space constants for a solitary erlectron in space.
May 09, 2010
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http://tinyurl.com/y9exvon
This applet is all based on Schroedinger equation and its solution is quite rigorous. It is using one initial condition, one Dirichlet condition and one integral condition (Sum(|Phi|^2)=1) - this is enough. You cannot do this solution more exact by adding more constants, which nobody requires.
http://www-teachi.../CO22.pd
May 10, 2010
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They are pure physics nonsense up to the point that one specifies the boundary conditions and check whether it makes physical sense.
A simple example which illustrates this fact is London's first equation for superconductors. The London brothers derived from it that the current must be a constant when the electric-field is zero. This constant is a boundary condition after the equation has been integrated. The conclusion that the current must be a constant is mathematically correct but not yet physics. To derive the physics involved one must specify the boundary condition: i.e. the constant. When doing this for a superconductor between two contacts, one finds that the only physically possible value for this constant is ZERO. But in text books it is argued that the London bros. have given a reason why a non-zero current can flow.
May 10, 2010
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As usual you are not answering what has been asked, but try and sideline the argument by referring to websites which have NOTHING to do with the original argument.
Let us try again. We have Schroedinger's equation and want to use it to model a solitary electron in space. In all text book it is assumed that one can put the potential energy term equal to zero. It is then derived that the electron can be represented by a single, infinite wave with only one space boundary condition which determines its intensity. This is NOT possible because the space coordinates have to be integrated twice. So I am asking again: Where is the other boundary condition?
May 10, 2010
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This is why another conditions are used: a combination of Dirichlet condition (which is asumming, potential differential is always zero at the sufficient distance from the center of wave packet) and an integral condition (which is assumming, the probability of the occurence of the wave packet over whole integration interval is unitary - we don't know exactly, where the particle is, but we can be perfectly sure, it will all be there).
You should learn a bit about solving of differential equations - putting constants on the boundary isn't far the only way, how to fit the solution.
May 10, 2010
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May 10, 2010
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I know about the Dirichlet condition etc. It is a fudge, just like the phase angle used to model superconduction is a fudge. It is an arbitrary boundary condition which cannot be used when you put the potential energy equal to zero. When doing the latter there is NO PHYSICAL reason why the intensity must drop off to zero at large distances. You can just as well assume that you do have a particle in a box. The Dirichlet criterion is just another way of introducing this same inconsistency.
What you should do is to learn basic mathematics and logic.
May 10, 2010
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This is another fudge: There is no exclusive experimental proof whatsoever that it is the vacuum fluctuating. All the arguments and experimental results used to postulate this stupidity can be explained in a better fashion without ending up with an infinite vacuum energy and renormalisation. When you get infinities in your calculations it is mathematics telling you that you are wrong!
Why did you decide to now start posting as ZeroX, Alizee? Have you got a split personality. However, one does need one to believe in your arguments!
May 10, 2010
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For example liquid hellium never freeze at room pressure, even at zero temperature, because its atoms are moving wildly.
It could be explained in similar way, like the Brownian motion of pollen grain in water, whose fluctuations keep these grains in eternal motion - even at the completelly calm watter surface.
I'm posting like ZeroX, because I'm using a different computer by now and I forget the password. I don't require people to believe in my arguments, only to understand them. This discussion shouldn't be based on belief and religion.
May 10, 2010
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If you don't believe in vacuum fluctuations, then there is no objective reason, why just this condition should be violated in some way. Until you demonstrate some counter-example, indeed.
As you can see, just the fact, the free particle doesn't expand in vacuum into infinity could serve as an (indirect) proof of vacuum fluctuations from perspective of steady-state solution of Schrodinger equation. Everything fits perfectly, here.
May 10, 2010
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Where was liquid helium cooled to absolute zero temperature so that you can make such a statement?
The reason why the He-atoms, which by the way are not "atoms" anymore when they form a superfluid (each is a single holistic wave) is that Heisenberg's relationship for energy and time allows such holistic waves to change their energies for short time intervals: i.e. by quantum fluctuations. This is the same way in which superconduction occurs. Thus in a sense you are correct that the energy is supplied by the "vacuum" but not by the "infinitely" large vacuum energy (quantum foam) as modelled by you.
May 10, 2010
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This is where we will never agree since the intensity distribution of a matter wave is IN MOST CASES not commensurate with a "probability distribution".
It does not because you are not specifying the reference frame in which you are modelling the electron: Thus violating Einstein's Special Relativity.
The reason why an electron wave does not spread in vacuum is that it MUST be a stationary, time-independent wave which does not change its shape and size with time within its inertial refrence frame.
There exists a non-zero potential energy which ties the wave down within its inertial reference frame.
May 10, 2010
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You see - suddenly Heissenberg's uncertainty principle appears good enough for you...;-) Of course, we should ask further, why some uncertainty principle should be valid at all? Which/where is the physical origin of this uncertainty?
May 10, 2010
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May 10, 2010
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Nice try: But you will note that I have NOT called it an "uncertainty" relationship because that is NOT what it is. It is a resonance- relationship which allows a holistic wave to vary its energy by an interval (del)E as long as it is not for longer than (del)t. You can easily derive this fact from the width's of atomic emission lines. In fact you can apply this to ALL waves when they resonate: Also to a light wave being received by a radio antenna. This is where it comes from: Purely from wave behaviour which has been well-known LONG before quantum mechanics came along.
May 10, 2010
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Similarly Heisenberg's relationship for position and momentum is NOT an uncertainty relationship for the position and momentum of a "particle". It is purely the sizes of the wave in position and k-space when it is a standing wave. This has also been known LONG before quantum mechanics. So why should this be the case FOR ALL harmonic waves EVER KNOWN but not for an electron wave? Furthermore why should the total intensity of ALL harmonic waves EVER KNOWN be equal to their energies, but when it comes to a harmonic electron wave it suddenly is not so? Obviously IT MUST STILL be so so that the intensity is the mass of the wave. It is simple and it shows that their is NO DICHOTOMY between quantum mechanics and classical physics at all!
May 10, 2010
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Because Galileo said so and Newton quantified the fact that an entity with mass MUST be stationary within its own inertial reference frame. This is why it is so: And this is why the use of mass in any equation (and thus also Schroedinger's wave equation) mmandates that it must be so. This is why interpreting the sizes of a wave in position and k-spaces as "uncertainties" in position and momentum invalidates ALL physics which came before Heisenberg, Born and Bohr touted the absurd probability interpretation. It is also so that when jettisoning the probability interpretation, classical mechanics, quantum mechanics and Einstein's gravity dovetails without any major problems.
May 10, 2010
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As I told you already, uncertainty principle enables to violate the stable position of these reference frames by quantum fluctuations of vacuum. When density of environment around massive object is fluctuating, for light waves, which are affected by such density fluctations such object is moving anyway. You cannot provide stable inertial frame for small object in dynamic vacuum.
May 10, 2010
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For example, on the macro scale we see black holes have a "small" size and a "large" size. The difference between the two is due to the interactions between the attractive forces of gravity upon matter and the repulsive forces of radiation escape pressure. We very well could be looking at a rehash on the micro scale with a different set of forces, or a corresponding analogy to the large forces on a smaller scale.
May 10, 2010
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http://tinyurl.com/36fql36
Such dance is nothing special, the same motion exhibit the density fluctuation inside of dense gas. And the above animation is the result of solution of Schrodinger equation inside of potential hole, i.e. with providing all integration constants, which you're requiring. As you can see, the resulting wave not only changes its energy, but the location too. It's actually moving like pollen grain under Brownian noise.
May 10, 2010
Rank: 1 / 5 (1)
May 10, 2010
Rank: 5 / 5 (1)
I'm sorry, can you say pseudoscience? Quantum motion is not directly observable, and definitely not by use of base human senses.
May 10, 2010
Rank: 1 / 5 (1)
http://www.youtub...aWCXkSC0
May 10, 2010
Rank: 5 / 5 (1)
The ability of a wave to resonate when required to do so when the boundray conditions require it to do so has nothing to do with the uncertainty of a point particle which requires it to be described by a wave whose intensity is a probability distribution. That holistic waves can jump around at low temperatures owing to quantum fluctuations does not mean there is any uncertainty involved at all.
There is not a most probable position of the wave around which a particle is fluctuating. The wave has a centre of mass and quantum fluctuations causes the wave to move like any other object with a centre-of-mass when it is vibrated. So there is no uncertainty involved.
May 10, 2010
Rank: 5 / 5 (2)
It is the centre of mass of the wave that moves when the wave moves NOT the inertial reference frame. So you are again talking nonsense. The Copenhagen interpretation of uncertainties does not come into the picture anywhere!
You are confusing ordinary statistical behaviour like Brownian movement with the statistical behaviour that has been postulated by Bohr, Born and Heisenberg. If you do not understand the difference you should again read a book on elementary quantum mechanics.
May 10, 2010
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As two scientists who have engaged in these sorts of conversations before, from me to you, you now know that the being known as zerox/alizee/slotin/alexa/etc... is merely a wanna be sophist and woefully ignorant of the reality of quantum mechanics and standard physical concepts. Why have you spent so much time trying to exemplify your addendum to the body of prior work when this slug can't understand the prior work, let alone, the addendum? Is it your love of teaching and knowledge or your want for a good fight that leads you to commit this repeated self insanity mechanism?
May 10, 2010
Rank: 5 / 5 (2)
No not a good fight. What worries me at present is that the physics community is more willing to classify a person as a crank than trying to understand: Yes there are many cranks around and yes since the advent of desktop computers they are flooding the system with wrong insights: However, I believe that it is incumbent on a scientist to argue and explain the science to everybody in as simple a fashion as possible. If we are not willing to do this we might be throwing out the baby with the bathwater in some cases. I have seen this happen too often lately to shirk reponsibilty in the same way. Even a fool can make a point or ask a relevant question from which one can learn.
May 10, 2010
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May 10, 2010
Rank: 1 / 5 (1)
If not, then it's useless and the controversy of yours cannot be judged experimentally - end of story. If yes, then just show us the difference.
Currently both probabilistic interpretation of QM, both uncertainty principle, both particle wave duality are concepts well supported by number of experiments. Can you provide some experiment, which violates the above concepts?
You cannot disprove some abstract concept just by another abstract concepts only. From Occam's razor follows, mainstream physics will not accept any concept, which doesn't bring any new prediction or which doesn't decrease the number of existing postulates and/or theories from utilitarian reasons.
May 10, 2010
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No, I evaluate and prefer to not interject when it is unwarranted. It has become warranted.
May 10, 2010
Rank: 1 / 5 (1)
Can you provide some experiment, which violates the above concepts? If not, then you can simply follow Mr. Prins for the assembly point of crackpots.
From perspective of aether theory it's exactly the same stuff. Just the particles of vacuum are tinier, then the particles of ordinary gas.
May 10, 2010
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This is of course a lie! I have given incontrovertible proof that the probability interpretation is wrong. As already mentioned many times in this forum, a probability distribution for the position of an electron for which the "most probable position" to find the electron is at a position where the intensity of the distribution is ZERO cannot be a probability distribution of an electron's position. As Einstein said: Only a single small fact is required to prove that a theory is wrong.
The proof is incontrovertible!
May 10, 2010
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Every other proof is controvertible, you know...
It isn't. It's a probability distribution of the occurrence of particle.
May 10, 2010
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Give me such an incontrovertible proof. You cannot.
I assume that what you are saying is that it does not require a most probable position. If not, around which position do you calculate Heisenberg's "uncertainty" interval for position? Or does this uncertainty not apply for a wave for which the most probable position is zero? Thus Heisenberg's relationship is null and void for most electrons?
May 10, 2010
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Frankly, did you really spent whole rest of your life in fight for the nonexistence of probability of electron's location at the place, where such probability is zero? I just cannot believe it...
May 10, 2010
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This is a stupid remark which do not really deserve a response. It seems you are at the end of your tether and is now becoming abusive instead of explaining how an uncertainty interval of position can be present around a position at which one can NEVER find an electron.
May 10, 2010
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Have look at this picture .. It illustrates the electron, which revolves atom nuclei along many paths. As the result, a two-lobe orbital is formed, analogous to common p-orbitals.
http://tinyurl.com/35urv4c
As you can see, at the center of orbital is zero probability of electron occurrence, where you can NEVER find an electron.
May 10, 2010
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What you have done is to prove my case: i.e. that the wave-intensity cannot be a probability distribution which defines a Heisenberg "uncertainty" interval; or else the highest intensity would have had to be at the position where you can NEVER find an electron. Thanks for proving so eloquently exactly what I am saying.
May 10, 2010
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LOL, why not? Such P-orbitals with two lobes are defining the shape of most molecules.
http://www.grandi...tals.gif
Such orbitals are just computed as a solution of electron wave function.
May 10, 2010
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Exactly! This is why the wave-intensities of "electrons" are real waves and the "most probable position" as interpreted by the Copenhagen interpretation is the centre-of mass of the wave. The latter can be at a position where the mass-intensity is zero. The most probable position cannot be at a position where a "probability distribution" has zero-intensity.
You keep on proving me right; Namely that the probability interpretation, wave-particle duality and complementarity are all unphysical: In fact these concepts are just plain nonsense! Thanks again! It is unbelievable that physicists could have believed in such claptrap for nearly 80 years.
May 10, 2010
Rank: 3 / 5 (2)
LOL - you're unable to face arguments and argument seriously. Now I can understand perfectly, why everybody ignores you.
May 10, 2010
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Thus you have TWO uncertainty intervals per electron? WOW!!
Not true. To form bonds from p-orbitals you have hybridisation. Seeing that it is impossible to instruct you in the simple physics of atomic orbitals I will not even try to tell you about chemistry. It is obviously far beyond you capabiliy!
May 10, 2010
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May 10, 2010
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I ask again: Which experiments and observations "support" this nonsense.
Again, you are just proving that you know NOTHING about chemical bonding: So let us not meander into that field which you are obviously unable to EVER understand!
May 10, 2010
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May 10, 2010
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You are just wasting everybody's time since two or more uncertainty intervals per electron TOTALLY invalidates the probability interpretation of the wave intensity. If you cannot see this, you should rather stop flooding forums like this one with claptrap.
May 10, 2010
Rank: 1 / 5 (1)
How do you want to explain the existence of angled molecules, if the probability of all electron waves would sit just at the center of their mass, like at the case of spherical wave? Try to draw a picture of such electron wave, which would allow it.
Frankly - I don't think, you could ever get Nobel price with such ideas, sorry... Some people are predestined to remain hidden at the shadows.
May 10, 2010
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I told you that I am not going to discuss chemical bonding with you since you clearly are incapable of understanding it. Obviously during cnemical bonding the centre-of-mass of the bond does NOT have to coincide with the nuclei. It is simple to derive that for a covalent bond the centre-of-mass of the boson-wave now fallsmidway between the nuclei. Possibly too difficult for you to compreend! But this does not change the fact that for all electron waves around a nucleus the centre-of-mass must coincide with the centre-of mass of the nucleus.
May 10, 2010
Rank: 1 / 5 (1)
http://pipeline.c...m/carbon orbitals.jpg
May 10, 2010
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Can you NOT get it through your skull that the intensity of an electron wave is NOT a probability distribution but the distibution of the wave's mass? And that any mass-distribution has a centre of mass! When an angled molecule is held together by covalent bonds the centre-of mass of each bond is situated at midpoint between the two nuclei it is bonding! Good God man you really cannot be so stupid can you?
May 10, 2010
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There is NO PROBABILITY involved whatsoever!!!!!! There is no harmonic wave in the universe which has an intensity distribution which is a probability distribution. The intensities of ALL harmonic waves have ALWAYS been their energies and will ALWAYS be their energies!
Good night! I pray that you try and do some thinking by tomorrow; if you are capabl;e of it.
May 10, 2010
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Intensity is intensity, energy is energy - these two quantities cannot be mixed. In probabilistic intepretation of quantum mechanics the probability of particle distribution correspond the square of square of the wavefunction.
May 10, 2010
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May 10, 2010
Rank: 1 / 5 (2)
http://www.physor...comments
Please, use the private message feature for contacting me regarding this stuff.
May 11, 2010
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Obviously the charge is also distributed within the wave and the charge-centre must coincide with the centre-of-mass. Charge is, however NOT energy but mass is: Therefore the intensity of the wave is its mass distribution. The wave does not have "spin": It has a magnetic moment just like a light-wave has a magnetic component.
For ALL fields and wave-fields EVER KNOWN the intensity is the energy of the field. Now you come along and state that they cannot be the same!!! I think you need to read an elementary physics-book on fields.
May 11, 2010
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This remark explains a lot about your incapability to argue physics in a logical manner above: It is beneath contempt.
May 11, 2010
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Intensity is nothing, what I could define/compare with experiment in conection to Schrodinger equation and some interpretations of it. For example, intensity of radiation flux is flow of energy per unit of time. If intensity is both energy, both mass distribution, then I'm really confused by your terms.
May 11, 2010
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Not "quantum mechanics" but the Copenhagen interpretation which is only valid in Alice's (or is it Alexa's) wonderland. You are NOT contributing when you just quote dogma which is obviously wrong since it is not based on reality and therefore cannot dovetail with classical mechanics and Einstein's gravity.
May 11, 2010
Rank: 2.6 / 5 (5)
http://vergil.che...e20.html
May 11, 2010
Rank: 5 / 5 (1)
Do you want to tell me that the word "imanent" makes these postulates holy dogma which was brought down from Mount Sinai by Moses?
You are wasting my time and everybody's time on this forum. Let us agree to disagree. I maintain that the present interpretation of quantum mechanics is wrong. You maintain that it is correct. You kept on promising that you will quote experimental results to prove your point but you never do. I have better things to do than to argue with a person who never answrs points raised but repeats wrong dogma in a mantra-type fashion.
So when you calculate (psi)(psi)* you are not calculating an intensity field. Really if talking nonsense was a spot you would have been a leopard!
May 11, 2010
Rank: 3 / 5 (4)
Intensity of what? Nope, the product (psi)(psi) is probability density.
http://tinyurl.com/3ank6b7
Sorry proffesor - with full respect, it's just you, who didn't understood the rules. You needn't to convince me about postulates of QM, because I didn't invented quantum mechanics, so I cannot change its postulates. If you believe, these postulates are saying something different, then the publicly awailable sources - then it's your problem, not mine and it's you, who is wasting the time of other readers, not me.
I hope, I'm clear by now.
May 11, 2010
Rank: 3.7 / 5 (3)
May 11, 2010
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That's a really big misunderstanding to have. One that effectively invalidates the majority of what you've said above.
May 11, 2010
Rank: 5 / 5 (1)
I did not want to respond to your assinine comments anymore. But I am getting tired that you claim experimental support without being able to supply it! PLEASE NOTE that a "postulate" is not an experimental proof!
May 11, 2010
Rank: 2 / 5 (4)
Without it it's still just a semantic twaddling. Maybe my comments may sound assinine for someone - but for me they're quite legitimate.
I met with many experts already, who claimed for example, the only acceptable model of reality is universe without time, or the vacuum composed of energy - but when I asked them for the real consequences of their breakthrough, they weren't able to provide any answer, only personal attacks.
http://imgs.xkcd....eory.png
Frankly, such stance is nothing very new even in mainstream science, which Mr. Prins is fighting against so often.
May 11, 2010
Rank: 5 / 5 (1)
Semantics? You yourself has said clearly that the probability interpretation cannot be reconciled with classical physics. The interpretation that the intensities of all waves are their energies immediately reconciles quantum mechanics with classiocal mechanics and Einstein's gravity, since one then has that both light and matter only exist of waves AND that one can model all interactions, also the photo-electric effect purely in terms of the known behaviour and interactions of waves. Particle interactions are not at all required. Is this twaddle? The only twaddle in physics has been wave-particle duality, probability waves, and complementarity. And of course your so-called ether models!
May 11, 2010
Rank: 2 / 5 (4)
http://www.physor...511.html
May 12, 2010
Rank: 5 / 5 (1)
You fooled me! I have dilligently looked in your comments for experimental evidence to support your ideas and found none to date!
The experiment that you just quoted above proves that "single particles" do not exist: Only waves. To obtain diffraction you must have a holistic wave which can split up into fragments which stay in immediate contact with each other. A particle can never diffract since, by definition of the properties of a particle, it cannot move through two slits simultaneously.
May 12, 2010
Rank: 2.6 / 5 (5)
Well, the particles doesn't move through two slits simultaneously. Believe it or not, this doesn't change the result of double slit experiment. What is spreading through both slits is just a deBroglie wave of vacuum, which is created around particles like wave around duck swimming at the river surface.
http://www.tinyurl.cz/oy7
Particle itself indeed remains quite tiny and well localized.
May 12, 2010
Rank: not rated yet
Pseudoscience again and a telling statement of ignorance on your part.
How exactly have you proven that a "wave of vaccuum" can have the characteristics of photons?
How exactly have you established that by passing through the barrier there is non-localized decay (of light...)?
Lastly, do you know what you're talking about?
May 12, 2010
Rank: 5 / 5 (2)
De Broglie wave of vacuum? Funny wave of vacuum which gives a double-slit diffraction pattern even though Alizee KNOWS that the "duck" only swims through one slit; but then do not interfere to give diffraction when Alizee confirms that the duck only swims through one slit.
May 12, 2010
Rank: 2.3 / 5 (3)
May 12, 2010
Rank: 1 / 5 (2)
As the result, you would swim along paths of interference maxims preferably. This effect at the undulating watter surface may not be quite minute, as Couder's group has found in somewhat different arrangement.
http://www.physor...511.html
May 13, 2010
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The photon-waves also create dots. The fact is that a wave changes its shape and size when its boundary conditions change. Within a screen the entities which can interact and absorb an impinging wave are of atomic size: This mandates that the impinging wave, no matter what its size before reaching the screen, must "collapse" into a smaller wave which then causes the spot. This happens for for both a photon-wave and an electron-wave. Thus "particles" are not needed to explain "spots" on the screen: They are caused by typical and classically well-known behaviour of waves.
May 13, 2010
Rank: 3 / 5 (4)
There is an interesting point too, gamma ray photons are spreading like massive particles (for example electrons), surrounded by its own deBroglie wave and gravity field., because their interference patterns are of the same character.
May 13, 2010
Rank: 5 / 5 (1)
If you don't understand why I'm asking for it you have no idea what a DeBroglie wave is. Especially if you think they can be composed of vaccuum.
May 13, 2010
Rank: 5 / 5 (1)
Nonsense!! A wave is a wave, and its wavelength
obviously determines what the smallest volume can be into which it can collapse. The fact that light waves with long wavelengths make larger spots is caused by the fact that only absorbers of larger size can collapse them than light-waves with shorter wavelengths.
The fact that gamma-waves spread like electron-waves is further proof that both entities are waves with short wavelengths and not particles at all.
May 13, 2010
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May 13, 2010
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May 13, 2010
Rank: 1 / 5 (2)
http://www.youtub...=related
In addition, these models are completely out of reach of formal math due their complexity. Even if we could compose their equations, we wouldn't be able to solve them. Even if we could solve them, we couldn't understand these solutions anyway due their complexity. The blind adherence of mainstream physics to formal math prohibits the physicists to see connections even at the place, where such connections are quite apparent.
May 13, 2010
Rank: 1 / 5 (2)
I'm not saying, equations are bad - but why to cover apparent connection of pilot wave and the wave around swimming duck at water surface, which everyone could imagine? Such stance appears childish at the first sight, but its deeper reasons are connected with tendency of mainstream science to keep its information monopoly for explanation of things like secretive shamans of medieval times.
If equations would remain the only way, how to explain the reality, then the scientists and teachers would always keep their job without public feedback like priests of ancient era. Such stance develops in every community out of public control.
May 13, 2010
Rank: 2.3 / 5 (3)
May 13, 2010
Rank: 1 / 5 (2)
Not at all. In the same mechanism the Hitler got its power in Germany - the whole reason was, every frustrated German hated Jews just a little bit more, then it's "normal". Such concentrated social pressure has enabled to survive psychopaths like Stalin or Hitler like condensation of evil inside of fluctuations of the dense particle gas. There was no underground conspiration against Jews, in fact - on the contrary, all their persecution was quite public.
In this way the particle model enables to understand the emergence of various social phenomena.
May 13, 2010
Rank: 1 / 5 (2)
The more surprising is, the physicists ignored dense aether model and its consequences so obstinately. The formal theorists of W.Pauli type have virtually some negative instinct for it - even the seemingly abstract and innocent concept of pilot wave was hated by these people just because it could leads to concept of dense aether, at least remotely. These formal theorists somehow recognized, it could be dangerous for them. In this connection the Towler's lecture "Not even wrong: Why does nobody like pilot-wave theory?" may be interesting for someone.
http://www.tcm.ph...ohm7.pdf
May 13, 2010
Rank: 1 / 5 (2)
"I personally didn't like pilot-wave theory, partly because it seems to me that it throws out all the deep, amazing and experimentally verified links between modern physics and mathematics that motivate what I love about the subjects, getting nothing much in return."
Do you see? Even formal mathematician can recognize instinctively, the pilot wave theory could lead into concepts, which would make his beloved math less significant in the eyes of society. He doesn't care, if it could lead to deeper understanding of physic, though.
The true nature of idiosyncrasy of mainstream science toward Aether theory is in the fight for social dominance of scientific community, in fact. We could say, Woit fights for public attention by his stance in the same way, like me.
May 13, 2010
Rank: 5 / 5 (2)
We established that the Universe wasn't composed of heavenly water a long time ago. Since then we've actually gone to space and proven that is wasn't a heavenly water.
There is no "dense aether".
Conceptual simplicity is akin to creationist cosmology.
May 13, 2010
Rank: 1 / 5 (3)
Why are so sure about it? The only person who proposed the "dense aether" concept before me was Oliver Lodge before one hundred years. But how his hypothesis was opposed and disproved? There is no evidence of refusal of this model inside of scientific community. Therefore you cannot know, whether "dense aether" exist or not.This is just another persuasive maneuver. After all, BigBang is conceptually even simpler
May 13, 2010
Rank: 5 / 5 (2)
Every "(energy) density fluctuation" (as you like to call it) causes a space-time curvature fluctuation. So every, even the tinniest single energy wave/particle/whatnot, that flies through it, causes a fluctuation of some sort & amplitude. Interactions between them the more.
There you have your quantum (soap?) foam.. Nothing more than just an interferrence pattern, and no hocus-pocus stuff popping out of nowhere from nothing in "empty" vacuum involved.
May 13, 2010
Rank: 5 / 5 (3)
Serriously.. I've seen you so many times trying to "adapt" various popular (pseudo)scientific gimmicks and stuff, even from theories/hypotheses that are mutually totally incompatible, that by now, it's really hard for me to believe a word from that quote above..
May 14, 2010
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The simplest and consistent model is that both matter and light consist solely of waves. All interactions between matter and light can then be modelled by solving differential wave equations. So the problem lies with YOU Alizee, Alexa, Seneca, XeroX or whatever personality you really have!
SO:
For half-educated trolls like Alizee, Xerox, Seneca, Alexa etc. the meaning of life is to prohibit the spreading of analogies and connections by all means possible. They're useless parasites of human society. What these people afraid of - the understanding of reality doesn't harm anyone?
May 14, 2010
Rank: 3 / 5 (4)
May 14, 2010
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Your model has succeeded in this repect since only a person with no intellect at all will not see that you are more of the track than mainstream physics can EVER HOPE TO BE.
May 14, 2010
Rank: 3 / 5 (4)
In this way, many mainstream physicists have literally no chance to recognize emergent logical patterns in fast growing pile of new ideas because of limited speed of information spreading inside of human society. Therefore the establishing of more general and fuzzy meta-theories could be understood as a sort of undeniable physical process.
The people would require meta-theories for to navigate in growing ocean of information faster in the same way, like they're undulating along foamy density fluctuations (branes) through vacuum.
May 14, 2010
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You succeeded in fooling me!! I have not seen a SINGLE logical connection in any of your propaganda for your aether theory. Or do you believe like Joseph Goebbels did that by just repeating the illogical enough people will believe that it is true?
May 14, 2010
Rank: 3.3 / 5 (4)
1) gas contains density fluctuations => in dense gas these fluctuations appear like membranes of foam or water surface
2) vacuum is dense gas => vacuum contains membranes of foam, which appear like watter surface
3) swimming duck forms a ripples around it at water surface => massive particle forms a ripples around it at the surfaces of foam.
Are you able to follow this logic - or do you see some hole in it?
May 14, 2010
Rank: not rated yet
There is no experimental proof for this assertion. Starting off with postulates which cannot be proved experimentally usually creates nonsense; as your model is doing;
OK, OK, I have closed my eyes and saw little ducks swimming past creating ripples in a foam of infinite density. I think I need a psychiatrist now!
May 14, 2010
Rank: 3 / 5 (4)
Of course they didn't do it, because it would enable the people to understand many trivialities, too. From the same reasons, druids and shamans didn't explained their tricks to the rest of society, even at the case, when they had logical explanations for it. They would lost their mystery, power and... jobs.
In this way modern physics catched itself into trap of its own positivism.
May 14, 2010
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I agree that string and quantum loop theory fall in the same category as your aether theory: It is all just claptrap!
May 14, 2010
Rank: 3 / 5 (4)
Does light travel in transversal waves like energy through dense gas? Did we talk about eternal motion of fluid helium like about Brownian motion of pollen grains in fluid? etc...
May 14, 2010
Rank: 5 / 5 (1)
Because there are no experimental data which support these theories in any manner whatsoever.
There is not even related experimental data from which one can argue that they might have any merit. That is why!
May 14, 2010
Rank: 5 / 5 (2)
It does not since if it did Einstein's Special Relativity would be wrong.
If you know elementary physics you will know that liquid helium and Brownian motion have NOTHING in common!
May 14, 2010
Rank: 5 / 5 (1)
If you want to believe such nonsense you are welcome to do so. The helium atoms move by quantum fluctuations which are allowed by Heisenberg's relationship for energy and time. They are not buffeted by non-existent "particles" constituting a so-calle aether.
I am not even going to try and reason with you about Einstein's special teory of relativity. It is clear that you do not understand it and do not want to understand it.
So good luck to you!! Maybe you should contact Mark MacCutcheon: He still believes that the planets are being "pushed" around their orbits.
May 14, 2010
Rank: 2.3 / 5 (3)
The same is valid about invariance of light speed in relativity. In this theory the invariance of light speed is one of postulates as a part of Lorentz symmetry. In dense aether theory it's a theorem, i.e. a consequence of transversal character of energy spreading in common dense massive environments.
In dense aether theory everything has its own very good logical reason, including the zero-point energy, uncertainty principle and/or invariance of light speed to the motion of environment. This theory proposes testable connection with observable reality for all phenomena and concepts of formal theories, so I'm not required to believe in any postulate, which hasn't support in everyday reality.
May 14, 2010
Rank: 1 / 5 (4)
http://www.physor...053.html
May 14, 2010
Rank: 4 / 5 (1)
It is NOT!!! It is a relationship that is NOT an "uncertainty" relationship. This is where the Copenhagenists went off the rails. It is purely a resonance relationship.
Thank God for small mercies!
May 15, 2010
Rank: 1 / 5 (2)
The phenomena, which are caused by many invisible artifacts, are generally labeled as probabilistic and I don't see nothing wrong in such denomination. It's simply the expression of the invisibility/undetectability of these artifacts and their hidden origins.
May 15, 2010
Rank: 1 / 5 (2)
My aether wave theory covers both models - both particle interpretation of gas, both wave interference model, because both these perspectives seamlessly converge and undulate mutually. The large system of particle exhibits waves, the large system of waves exhibits interference wave packets, i.e. particles. From perspective of dense aether model both these systems are the very same stuff conceptually.
Therefore I can understand your fight for wave interference interpretation of quantum uncertainty quite well, but from my perspective such wave interpretation is just one of aspects of more general model of hyper-dimensional reality. Some aspects of this reality are easier to describe by using of particles, some others in waves.
May 15, 2010
Rank: 5 / 5 (1)
Just to demonstrate how serious he is.
May 15, 2010
Rank: 1 / 5 (1)
"to be serious" doesn't equal "to be true"
It's evident, my opponents aren't interested about discussion, but for silencing of discussion and disregarding of their opponents.
Jun 05, 2010
Rank: not rated yet
The words can be common to all.
Neologism
"for exact understanding exact language is necessary."
(Gurdjieff to Ouspensky)
You need no judgment or defense.
You need to be understood.
You need to understand others do not understand you.
I need to know you know a language - a language that has meaning - beyond the language you understand.
My understanding is irrelevant.
Everyone understanding is relevant except mine.
Nothing is so wonderful it can not be repeated.
Including mutual understanding.